I am trying to write an Angular Regex validator, which matches this and only this pattern for phone, spaces exact How can this be done? Working on this Code: Trying to add the space, after the first parenthesis, not sure if correct Answer You need to Add a literal space (or s to allow any whitespace) exactly at the location where you expect it to be in the string Escape the ( char after ^ because you need to match a literal open parenthesis. Do not escape – that is outside of a character class, i.e. not inside […]. You
I’m really stuck again on how to properly combine these lines to auto-replace straight quotes into smart ones in the text area. It was working earlier, however after I added a line to fix the cursor going at the end after replacing a character. Here’s what is currently looks like: Commas, semicolon, period, em dash, and double spaces is working already.But it’s not for the quote marks. What can I do to correct these regex lines? Here’s exactly where I’m stuck: Thanks in advance Answer In your replaceText you need to distinguish when you pass a regex or a string.
I have a long string containing some special characters. I need to check those special characters who do not follow space and replace it with a special character and space. Example Input Output Here you can see the last < replaced with < as it follows z which is not space. Keep this in mind in the HTML the special characters are coming in entities like Regex solution will be great. Answer Description of the pattern: a ” < ” character that is not followed by a white-space
I have a string as follows: I’m trying to get rid of the characters between the backslashes. Wanted result: I know how to remove everything except characters between two special characters WITHOUT removing the special characters. Every answer on stack includes removing them too 🙁 Answer Put the backslashes in the replacement string. Note that you need to double them to get literal backslashes because backslash is an escape prefix in string literals. This result doesn’t match the result in your example, but that’s because it doesn’t match your description of what you want to do. I implemented the description.
I have string in JS which where I need to add ‘ to the values. Example: task: task one, client: Mr jhon will be converted to task:’task one’, client: ‘Mr Jhon’ Think of these string as user entered search query. This is then sent to the backed for the searching. The values need to be enclosed in ‘ Complexities taskname: one two three, client: Mr Jhon there can be more than 2 words taskname: one two, client: Mr Jhon more than 1 space taskname:one,client: Mr Jhon can be singe word without space priority:1,groupname: Mr Singh the name of can be
I have a dynamic template string, similar to the following: I also have an object like so: How do I replace each template variable with the value presented in an object where the key is the text in the braces. For example: I have tried the following: The code above replaces all instances of text in curly braces with undefined. I have looked at multiple StackOverflow questions, but none have addressed this issue. Answer Luckily, replace() allows to use a callback:
How can I limit a negative lookahead RegEx to an exact number of characters? For example, this sentence should be denied… This car is not that fast! while this one should be allowed… The car you are about to see may not be that fast, but it’s very beautiful! The RegEx should match any sentence that contains the word ‘car’, except the ones that include the word ‘not’ in the following 10 characters. This is the case of the first sentence, where there are only 4 characters in between the ‘car’ and ‘not’ words. So this sentence should be denied.
For example… (this fails) Is there a way to make this sort of thing work? $1 is available when it’s used in a string, but not as a key. Answer Unfortunately no, you’ll have to use a replacer function instead: Also note that you can use d instead of [0-9] instead, it makes the regex a bit nicer to read. If you don’t actually need the second group for something special, you can just echo back the match in the object: