I need two regular expressions, one to get ** at the beginning of a string, and one at the end. For example: With an expression obtain the ** of the beginning and with another those of the end. There may be many more repetitions. I have tried the following: Thanks a lot It should mark all the words that contain
Tag: regex
Does not conform date-time in ajv based middy validator
I use middy as validator package which is based on ajv, I set jsonschema like follows my request is ilke this,this is basically aligned with date-time But it returned following error response. I totally confused what is the wrong point of that. If someone has opinion ,please let me know. Thanks I found following list which come from validation packages.I
Regex to get last part of url without appended version and parameters
Hi guys I’ve got a very specific request where I would like to get the last part of a url without the parameters but if the name of the script has a version appended, like -V2, where the 2 could be any number, the regex would ignore it. So far I found this (?!/)(w+)(?=.js) but it is only getting a
Filter array with match regex only returning the first match (javascript)
I have to filter and map an array of strings into another array,the problem is that it only matches the first match and the other string doesnt match it when it should because I have tried the apttern on regex101 and it worked. I have an object called ‘stacks’ with multiple variables, for simplicity I only write the one im
Lookahead and Lookbehind validation for each letters in a string (Regular Expression XYX or XXX matching) [closed]
Closed. This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 7 months ago. Improve this question I need to find the letters which have the same letter before and after. Using regular expression how do that?
Creating a regular expression that replaces strings in quotes with empty strings [closed]
Closed. This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 7 months ago. Improve this question How can I create a regular expression that finds the text wrapped in “”” or ”’ for example: I want
How to rematch the first word or ‘(‘ the first word at the beginning
str = “find().nodes() as n3” ==> find str = “with n1,n2,n3” ===> with Answer Use string match with the regex pattern ^w+:
Javascript: Regex to convert a numbered list string to an array of items
I am trying to convert a numbered list into an array of items. This is what I have so far: This only produces the following output: What I would like is something like this: Why is it matching only one item out of this string? What am I doing wrong and how can I fix it? Answer Your regex does
Regex expression not returning entire term
The intention of the regex is to capture substrings wrapped between twin expressions in parentheses, kinda like html tags. For example: And here’s my code Can anyone tell me why this doesn’t capture the entire thing? Answer The characters () are special in a regexp and must be escaped with a if you want to match them literally. And
Need regex for project name with the following conditions
Need regex for the “Project name” with following condition. Expected Result: Take alphabetical, alpha numeric, alpha numeric symbolic Actual Result: that is, Everything is allowed but if it is just special characters and no text than it’s a problem. **Example: zjna5726$7&^#bsg //allowed %&*% // just special characters not allowed I tried /^[ A-Za-z0-9_@./#&+-]*$/ but did not help ^([w+d+]+)((-)([w+d+]+))* //did not