Tag: gulp

Error: Node Sass does not yet support your current environment: Windows 64-bit with Unsupported runtime (93)

Getting below error after installed latest node.js (v16.13.1) Error: Node Sass does not yet support your current environment: Windows 64-bit with Unsupported runtime (93) For more information on which environments are supported please see: https://github.com/sass/node-sass/releases/tag/v4.14.1 I have created static pages for my application and use sass and gulp I have a static pages and using Sass in the page and

Import two files

gulp gulp-sass import javascript npm

Recently started learning imports and faced the following problem After installing the package in gulpfile, you need to make the following entry: Can I somehow make this record using import? The only thing that comes to my mind is: But there one variable is assigned two values, and here, in fact, there are 2 “variables” and it turns out somehow

Trouble with splitting gulpfile.js into multiple files in Gulp 4

gulp gulp-4 javascript

I am a beginner to Javascript and Gulp. Am learning this based on a udemy course in which Gulp 3 is being used, and I’ve been looking at docs to convert the code to Gulp 4. It’s been fun so far since I am learning more when I am doing the conversions myself, but am stuck on this one. Wonder

Use gulp files from other npm packages (import files which will eventually exist)

gulp javascript node.js

I have one npm package containing several files with several gulp task definitions. What I want is in the main gulpfile, be able to copy these gulp files (from the package) and execute the gulp tasks defined in them. Follows an example: The problem is: When I try to execute gulp debug, it is retrieved an error saying require(‘../src/generated-code/gulp/gulp.debug’) does

Ignore return outside of function with babel 7

babeljs gulp javascript webpack

I recently updated to babel 7 and webpack 4 and am receiving this error when running our gulp build task: This is caused by the return outside of a function in browser-syncs dev-ip dependency. Is there a way to configure my .babelrc file to ignore this? I’ve tried the following: Installing only production dependencies, but because browser sync is imported

gulp-remember seems to output wrong path

gulp gulp-cached gulp-rename javascript

[Using gulp 3.9.0, gulp-cached 1.1.0, gulp-remember 0.3.0, gulp-rename 1.2.2] We’re using gulp as a build tool and gulp-cached together with gulp-remember to allow fast incremental rebuilds. Part of the files under build have to be moved to a different output directory and this has to happen in-stream (i.e. not in gulp.dest()), because we’re zipping the results afterwards. We use gulp-rename

Running a shell command from gulp

gulp javascript

I would like to run a shell command from gulp, using gulp-shell. I see the following idiom being used the gulpfile. Is this the idiomatic way to run a command from a gulp task? Answer gulp-shell has been blacklisted. You should use gulp-exec instead, which has also a better documentation. For your case it actually states: Note: If you just

console.log to stdout on gulp events

gulp javascript node.js

I want to log to stdout (the config environment) when a gulp task is running or has run. Something like this: I am not sure what event I should be responding to or where to find a list of these. Any pointers? Many thanks. Answer (In December 2017, the gulp-util module, which provided logging, was deprecated. The Gulp team recommended

gulp – exclude a file when minifying CSS

gulp javascript optimization preprocessor

Im new to Gulp.. I have been able to successfully install and concatenate and minify my .js and .css files, however, there is one .css file which i want to exclude – print.css Ive followed the instructions here: https://www.npmjs.org/package/gulp-ignore install gulp-ignore in my local directory, and modified my gulpfile.js to: Within my CSS Task – Secure, i have included .pipe(exclude(‘Secure/css/print.css’))