What’s the shortest way (within reason) to generate a random alpha-numeric (uppercase, lowercase, and numbers) string in JavaScript to use as a probably-unique identifier?
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Answer
If you only want to allow specific characters, you could also do it like this:
function randomString(length, chars) { var result = ''; for (var i = length; i > 0; --i) result += chars[Math.floor(Math.random() * chars.length)]; return result; } var rString = randomString(32, '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ');
Here’s a jsfiddle to demonstrate: http://jsfiddle.net/wSQBx/
Another way to do it could be to use a special string that tells the function what types of characters to use. You could do that like this:
function randomString(length, chars) { var mask = ''; if (chars.indexOf('a') > -1) mask += 'abcdefghijklmnopqrstuvwxyz'; if (chars.indexOf('A') > -1) mask += 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'; if (chars.indexOf('#') > -1) mask += '0123456789'; if (chars.indexOf('!') > -1) mask += '~`!@#$%^&*()_+-={}[]:";'<>?,./|\'; var result = ''; for (var i = length; i > 0; --i) result += mask[Math.floor(Math.random() * mask.length)]; return result; } console.log(randomString(16, 'aA')); console.log(randomString(32, '#aA')); console.log(randomString(64, '#A!'));
Fiddle: http://jsfiddle.net/wSQBx/2/
Alternatively, to use the base36 method as described below you could do something like this:
function randomString(length) { return Math.round((Math.pow(36, length + 1) - Math.random() * Math.pow(36, length))).toString(36).slice(1); }