How to place floating action button in bottom right in React Native



I am trying to place a floating action button in the lower right corner of my app but it is placing it in the top left way off screen.

Returned view:

<View>
   <View style={{flexDirection: 'row'}}>
      <TouchableOpacity onPress={this.onPress} activeOpacity={.5} >
          <Image
              source={require('./assets/images/hamburger.png')}
              style={{ width: 30, height: 25,  marginLeft: 15}}
          />
      </TouchableOpacity>
   </View>
   <FloatingAction style={styles.bottom}/>
</View>

Styles:

const styles = StyleSheet.create({
  bottom: {
    flex: 1,
    position: 'absolute',
    bottom: 10,
    right:10
  },
});

My current view displays a header and a bottom tab view. I am able to place multiple FAB’s in each tab screen but that produces an undesirable behavior. Thank you for any help.

Edit: What I have:

What I want:

Answer

Your issue was on adding { flex: 1, position: 'absolute',} to the button style together. The parent component that covers all the phone screen would use flex: 1, your button component is the one that receives the style for the position.

Always creating a new component makes stuff easier to read and understand. So let’s say you have a button component (<FloatingButton/>), you would do something like this:

import React from 'react';
import { Text, View, StyleSheet } from 'react-native';
import FloatingButton from './FloatingButton';

export default class App extends React.Component {
  render() {
    return (
      <View style={styles.container}>
        <Text>
          I'm just a Text
        </Text>

        <FloatingButton 
          style={styles.floatinBtn}
          onPress={() => alert(`I'm being clicked!`)}
        />
      </View>
    );
  }
}

const styles = StyleSheet.create({
  container: {
    flex: 1,
    justifyContent: 'center',
    alignItems: 'center',
  },
  floatinBtn: {
    
    position: 'absolute',
    bottom: 10,
    right: 10,
  }
});

You will get this result:

This is the button component:

import React from 'react';
import { View, TouchableOpacity } from 'react-native';

export default props => (
  <TouchableOpacity onPress={props.onPress} style={props.style}>
    <View
      style={{
        backgroundColor: 'blue',
        width: 45,
        height: 45,
        borderRadius: 45,
      }}
    />
  </TouchableOpacity>
);

Check the snack demo: https://snack.expo.io/@abranhe/floating-btn



Source: stackoverflow