I’m trying to create a tree view (and dump that into a Google sheet) of our OrgUnits. I have the following script which pulls and sorts the data:
function listAllOUs() { const ouArray = [] const page = AdminDirectory.Orgunits.list('my_customer', { orgUnitPath: '/', type: 'all' }); const orgUnits = page.organizationUnits; if (orgUnits) { for (let i = 0; i < orgUnits.length; i++) { const orgUnit = orgUnits[i]; ouArray.push(orgUnit.orgUnitPath) } } else { Logger.log('Could not find any OUs'); } ouArray.sort() }
The above code produces the array called ouArray
, which looks like this:
[/Parent_01, /Parent_01/Child_01, /Parent_01/Child_01/Grandchild_01, /Parent_01/Child_02, /Parent_01/Child_03, /Parent_01/Child_04, /Parent_02, /Parent_02/Child_01, /Parent_02/Child_02, /Parent_02/Child_02/Grandchild_01, /Parent_02/Child_05, /Parent_02/Child_06, /Parent_02/Child_07, /Parent_02/Child_07/Grandchild_01, /Parent_02/Child_08, /Parent_02/Child_09, /Parent_02/Child_09/Grandchild_01, /Parent_02/Child_3, /Parent_02/Child_4, /Parent_03, /Parent_03/Child_01, /Parent_03/Child_01/Grandchild_01, /Parent_03/Child_02, /Parent_03/Child_02/Grandchild_01, /Parent_03/Child_02/Grandchild_02, /Parent_03/Child_03, /Parent_03/Child_03/Grandchild_01, /Parent_03/Child_03/Grandchild_02, /Parent_03/Child_04, /Parent_03/Child_05, /Parent_03/Child_05/Grandchild_01, /Parent_03/Child_05/Grandchild_02, /Parent_10, /Parent_11]
Now what I want to do is take that data, and format it and place it into a Google Sheet so that it resembles this:
+====+============+=====================+===================================+ | | A | B | C | +====+============+=====================+===================================+ | 1 | /Parent_01 | | | +----+------------+---------------------+-----------------------------------+ | 2 | | /Parent_01/Child_01 | | +----+------------+---------------------+-----------------------------------+ | 3 | | | /Parent_01/Child_01/Grandchild_01 | +----+------------+---------------------+-----------------------------------+ | 4 | | /Parent_01/Child_02 | | +----+------------+---------------------+-----------------------------------+ | 5 | | /Parent_01/Child_03 | | +----+------------+---------------------+-----------------------------------+ | 6 | | /Parent_01/Child_04 | | +----+------------+---------------------+-----------------------------------+ | 7 | /Parent_02 | | | +----+------------+---------------------+-----------------------------------+ | 8 | | /Parent_02/Child_01 | | +----+------------+---------------------+-----------------------------------+ | 9 | | /Parent_02/Child_02 | | +----+------------+---------------------+-----------------------------------+ | 10 | | | /Parent_02/Child_02/Grandchild_01 | +----+------------+---------------------+-----------------------------------+ | 11 | | /Parent_02/Child_05 | | +----+------------+---------------------+-----------------------------------+ | 12 | | /Parent_02/Child_06 | | +----+------------+---------------------+-----------------------------------+ | 13 | | /Parent_02/Child_07 | | +----+------------+---------------------+-----------------------------------+ | 14 | | | /Parent_02/Child_07/Grandchild_01 | +----+------------+---------------------+-----------------------------------+ | 15 | | /Parent_02/Child_08 | | +----+------------+---------------------+-----------------------------------+ | 16 | | /Parent_02/Child_09 | | +----+------------+---------------------+-----------------------------------+ | 17 | | | /Parent_02/Child_09/Grandchild_01 | +----+------------+---------------------+-----------------------------------+ | 18 | | /Parent_02/Child_3 | | +----+------------+---------------------+-----------------------------------+ | 19 | | /Parent_02/Child_4 | | +----+------------+---------------------+-----------------------------------+ | 20 | /Parent_03 | | | +----+------------+---------------------+-----------------------------------+ | 21 | | /Parent_03/Child_01 | | +----+------------+---------------------+-----------------------------------+ | 22 | | | /Parent_03/Child_01/Grandchild_01 | +----+------------+---------------------+-----------------------------------+ | 23 | | /Parent_03/Child_02 | | +----+------------+---------------------+-----------------------------------+ | 24 | | | /Parent_03/Child_02/Grandchild_01 | +----+------------+---------------------+-----------------------------------+ | 25 | | | /Parent_03/Child_02/Grandchild_02 | +----+------------+---------------------+-----------------------------------+ | 26 | | /Parent_03/Child_03 | | +----+------------+---------------------+-----------------------------------+ | 27 | | | /Parent_03/Child_03/Grandchild_01 | +----+------------+---------------------+-----------------------------------+ | 28 | | | /Parent_03/Child_03/Grandchild_02 | +----+------------+---------------------+-----------------------------------+ | 29 | | /Parent_03/Child_04 | | +----+------------+---------------------+-----------------------------------+ | 30 | | /Parent_03/Child_05 | | +----+------------+---------------------+-----------------------------------+ | 31 | | | /Parent_03/Child_05/Grandchild_01 | +----+------------+---------------------+-----------------------------------+ | 32 | | | /Parent_03/Child_05/Grandchild_02 | +----+------------+---------------------+-----------------------------------+ | 33 | /Parent_10 | | | +----+------------+---------------------+-----------------------------------+ | 34 | /Parent_11 | | | +----+------------+---------------------+-----------------------------------+
If anyone has any idea’s on how I can accomplish this, it would be amazing. Logically (at least in my mind), it would need some kind of string/partial string match? But I can’t for the life of me figure it out!
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Answer
Explanation:
The logic of the following script is quite simple:
Iterate through
ouArray
and forEach element find the number of forward slashes/
.Use a nested ternary operator and for each of the possible cases push the corresponding array to the final
data
array.
In more detail:*
1
x/
: append[t,"",""]
,2
x/
: append["",t,""]
,3
x/
: append["","",t]
where t
is every element in ouArray
.
*(1
x/
means one forward slash etc.)
Complete Solution:
function listAllOUs() { // get spreadsheet details const ss = SpreadsheetApp.getActive(); const sh = ss.getSheetByName('Sheet1'); // choose the name of your sheet const ouArray = [] const page = AdminDirectory.Orgunits.list('my_customer', { orgUnitPath: '/', type: 'all' }); const orgUnits = page.organizationUnits; if (orgUnits) { for (let i = 0; i < orgUnits.length; i++) { const orgUnit = orgUnits[i]; ouArray.push(orgUnit.orgUnitPath) } } else { Logger.log('Could not find any OUs'); } ouArray.sort() data = []; ouArray.forEach(t=>{ let nslashes = [...t].filter(l => l === '/').length; data.push( nslashes==1?[t,"",""]: nslashes==2?["",t,""]:["","",t] ) }); // set the values back to the sheet sh.getRange(1,1,data.length,data[0].length).setValues(data); }
Reproducible example:
function myFunction() { const ss = SpreadsheetApp.getActive(); const sh = ss.getSheetByName('Sheet1'); // choose the name of your sheet const ouArray = ["/Parent_01", "/Parent_01/Child_01", "/Parent_01/Child_01/Grandchild_01", "/Parent_01/Child_02", "/Parent_01/Child_03", "/Parent_01/Child_04", "/Parent_02", "/Parent_02/Child_01", "/Parent_02/Child_02", "/Parent_02/Child_02/Grandchild_01", "/Parent_02/Child_05", "/Parent_02/Child_06", "/Parent_02/Child_07", "/Parent_02/Child_07/Grandchild_01", "/Parent_02/Child_08", "/Parent_02/Child_09"] data = []; ouArray.forEach(t=>{ let nslashes = [...t].filter(l => l === '/').length; data.push( nslashes==1?[t,"",""]: nslashes==2?["",t,""]:["","",t] ) }); sh.getRange(1,1,data.length,data[0].length).setValues(data); }