What is the python equivalent of JavaScript’s Array.prototype.some / every?

Does python have any equivalent to JavaScript’s Array.prototype.some / every?

Trivial JavaScript example:

var arr = [ "a", "b", "c" ];
arr.some(function (element, index) {
    console.log("index: " + index + ", element: " + element)
    if(element === "b"){
        return true;
    }
});

Will output:

index: 0, element: a
index: 1, element: b

The below python seems to be functionally equivalent, but I do not know if there is a more “pythonic” approach.

arr = [ "a", "b", "c" ]
for index, element in enumerate(arr):
    print("index: %i, element: %s" % (index, element))
    if element == "b":
        break

Answer

Python has all(iterable) and any(iterable). So if you make a generator or an iterator that does what you want, you can test it with those functions. For example:

some_is_b = any(x == 'b' for x in ary)
all_are_b = all(x == 'b' for x in ary)

They are actually defined in the documentation by their code equivalents. Does this look familiar?

def any(iterable):
    for element in iterable:
        if element:
            return True
    return False