I have to multiply the sign of all elements in an array.
For example 1:
input: [1, 2, 3] output: 1 Explain: 1 * 1 * 1 = 1
Ex2:
input: [1, -2, 3] output: -1 Explain: 1 * (-1) * 1 = -1
Ex3:
input: [1, -2, 3, 0] output: 0 Explain: 1 * (-1) * 1 * 0 = 0
And here is my solution
function cal(A) { return A.reduce((total, currentValue) => total * Math.sign(currentValue), 1); }
However, the output of ex3 cal([1, -2, 3, 0])
is -0
.
I’ve already thought about adding one more condition like this
function cal(A) { var total = A.reduce((total, currentValue) => total * Math.sign(currentValue), 1); if(total === 0) return 0; else return total; }
And obviously, It looks ugly. Is there a more elegant way to resolve that?
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Answer
In order to avoid conditional checks and keep the function purely computational you can use the curious rules of -0
to simply add 0 to the result of your reduce()
which will have no effect on non-zero results but will have the effect of converting -0
to 0
.
function cal(arr) { return arr.reduce((a, c) => a * Math.sign(c), 1) + 0; } console.log(cal([1, 2, 3])); // 1 console.log(cal([1, -2, 3])); // -1 console.log(cal([1, -2, 3, 0])); // 0
See signed zero for more general discussion.