After button click, show spinner icon on button while click event in progress

I’m trying to show spinner on button while loading on submit, I have seen a couple of implementations and tried in my application but its not working. Here is the fiddle which I am trying to describe. I want to mention one other thing that this HTML is on my sidebar and being added through javascript on ajax call

My JS

        (function () {
            $(document).on("click","#submitbutton", function (event) {
                $(this).addClass('active');
                var formdata = $("#filterdata").serializeArray();
                var url1 = "/SelectUnit";
                $.ajax({url: url1, data: formdata, type: 'GET', async:false .....}).done(function(){
    $(this).removeClass('active');

})
            });
            })();

   

 My CSS
    

.spinner {
          display: inline-block;
          opacity: 0;
          max-width: 0;
    
          -webkit-transition: opacity 0.25s, max-width 0.45s; 
          -moz-transition: opacity 0.25s, max-width 0.45s;
          -o-transition: opacity 0.25s, max-width 0.45s;
          transition: opacity 0.25s, max-width 0.45s; /* Duration fixed since we animate additional hidden width */
        }
    
        .has-spinner.active {
          cursor:progress;
        }
    
        .has-spinner.active .spinner {
          opacity: 1;
          max-width: 50px; /* More than it will ever come, notice that this affects on animation duration */
        }

My HTML
<div class="formbuttons">
            <button type="button" id="submitbutton" class="btn buttoncolor has-spinner">
                  <span class="spinner"><i class="icon-spin icon-refresh"></i></span>Select</button>
            <button type="button" class="btn buttoncolor" onclick="clearFilter();">Clear</button>
</div>

Answer

I made some changes (changed the icon and edited the CSS) in you code to be easier to test: http://jsfiddle.net/q1d06npq/4/

Instead of $.ajax().done() the best option in you case is to use the $.ajax().always() that is executed even if the ajax fails.

The code $(this) inside the callback function will not point to the button, to solve that you can use something like this: var elem = $(event.currentTarget);

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Answer