I’m learning to use scrapy with splash. As an exercise, I’m trying to visit https://www.ubereats.com/stores/, click on the address text box, enter a location and then press the Enter button to move to next page containing the restaurants available for that location. I have the following lua code:
function main(splash) local url = splash.args.url assert(splash:go(url)) assert(splash:wait(5)) local element = splash:select('.base_29SQWm') local bounds = element:bounds() assert(element:mouseclick{x = bounds.width/2, y = bounds.height/2}) assert(element:send_text("Wall Street")) assert(splash:send_keys("<Return>")) assert(splash:wait(5)) return { html = splash:html(), } end
When I click on “Render!” in the splash API, I get the following error message:
{ "info": { "message": "Lua error: [string "function main(splash)r..."]:7: attempt to index local 'element' (a nil value)", "type": "LUA_ERROR", "error": "attempt to index local 'element' (a nil value)", "source": "[string "function main(splash)r..."]", "line_number": 7 }, "error": 400, "type": "ScriptError", "description": "Error happened while executing Lua script" }
Somehow my css expression is false, resulting in splash trying to access an element that is undefined/nil! I’ve tried other expressions, but I can’t seem to figure it out!
Q: Does anyone know how to solve this problem?
EDIT: Even though I still would like to know how to actually click on the element, I figured out how to get the same result by just using keys:
function main(splash) local url = splash.args.url assert(splash:go(url)) assert(splash:wait(5)) splash:send_keys("<Tab>") splash:send_keys("<Tab>") splash:send_text("Wall Street, New York") splash:send_keys("<Return>") assert(splash:wait(10)) return { html = splash:html(), png = splash:png(), } end
However, returned html/images in the splash API are from the page where you enter the address, not the page that you see after you’ve entered your address and clicked enter.
Q2: How do I succesfully load the second page?
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Answer
Not a complete solution, but here is what I have so far:
import json import re import scrapy from scrapy_splash import SplashRequest class UberEatsSpider(scrapy.Spider): name = "ubereatspider" allowed_domains = ["ubereats.com"] def start_requests(self): script = """ function main(splash) local url = splash.args.url assert(splash:go(url)) assert(splash:wait(10)) splash:set_viewport_full() local search_input = splash:select('#address-selection-input') search_input:send_text("Wall Street, New York") assert(splash:wait(5)) local submit_button = splash:select('button[class^=submitButton_]') submit_button:click() assert(splash:wait(10)) return { html = splash:html(), png = splash:png(), } end """ headers = { 'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/55.0.2883.95 Safari/537.36' } yield SplashRequest('https://www.ubereats.com/new_york/', self.parse, endpoint='execute', args={ 'lua_source': script, 'wait': 5 }, splash_headers=headers, headers=headers) def parse(self, response): script = response.xpath("//script[contains(., 'cityName')]/text()").extract_first() pattern = re.compile(r"window.INITIAL_STATE = ({.*?});", re.MULTILINE | re.DOTALL) match = pattern.search(script) if match: data = match.group(1) data = json.loads(data) for place in data["marketplace"]["marketplaceStores"]["data"]["entity"]: print(place["title"])
Note the changes in the Lua script: I’ve located the search input, send the search text to it, then located the “Find” button and clicked it. On the screenshot, I did not see the search results loaded no matter the time delay I’ve set, but I’ve managed to get the restaurant names from the script
contents. The place
objects contain all the necessary information to filter the desired restaurants.
Also note that the URL I’m navigating to is the “New York” one (not the general “stores”).
I’m not completely sure why the search result page is not being loaded though, but hope it’ll be a good start for you and you can further improve this solution.