I need some help
I have two arrays:
First array have Boolean elements. (It’s true when button is active , and false if not)
The second one strings where “0”(active) or “1” (inactive).
let arrayBotoesCategorias = [iconCategoriaIndividual, iconCategoriaGrupo, iconCategoriaIndoor, iconCategoriaOutdoor, iconCategoriaAquatico,iconCategoriaNatureza]; let arrayCategorias = [item.individual, item.grupo, item.indoor, item.outdoor, item.aquatico, item.natureza];
To understand better , PaintBall have grupo(group), indoor, outdoor and natureza(nature) activated. The rest are inactive. Like this
individual: "0", grupo: "1", indoor: "1", outdoor: "1", aquatico: "0", natureza: "1",
What I need it’s the following but of course with another solution:
if(arrayBotoesCategorias[1] == true && arrayBotoesCategorias[2] == true && arrayBotoesCategorias[3] == true && arrayBotoesCategorias[5] == true){ if(arrayCategorias[1] == "1" && arrayCategorias[2] == "1" && arrayCategorias[3] == "1" && arrayCategorias[5] == "1"){ return(itemSection) } }
When a element from the first array is true and the same position of the second is == “1” , return something.
In this example image , I Want to show the images that have those 3 tables (outdoor, aquatico and natureza with value “1”);
Advertisement
Answer
Already solved Thanks for the help!
var controlCategorias = 0; var errorControlCategorias = 0; for(var i = 0; i<arrayBotoesCategorias.length; i++){ switch (i){ case 0: if((arrayBotoesCategorias[0] && item.individual == "1") || (!arrayBotoesCategorias[0] && item.individual == "0") || (!arrayBotoesCategorias[0] && item.individual == "1")) { controlCategorias++; }else{ errorControlCategorias++; } break; case 1: if((arrayBotoesCategorias[1] && item.grupo == "1") || (!arrayBotoesCategorias[1] && item.grupo == "0") || (!arrayBotoesCategorias[1] && item.grupo == "1")) { controlCategorias++; }else{ errorControlCategorias++; } break; case 2: if((arrayBotoesCategorias[2] && item.indoor == "1") || (!arrayBotoesCategorias[2] && item.indoor == "0") || (!arrayBotoesCategorias[2] && item.indoor == "1")) { controlCategorias++; }else{ errorControlCategorias++; } break; case 3: if((arrayBotoesCategorias[3] && item.outdoor == "1") || (!arrayBotoesCategorias[3] && item.outdoor == "0") || (!arrayBotoesCategorias[3] && item.outdoor == "1")) { controlCategorias++; }else{ errorControlCategorias++; } break; case 4: if((arrayBotoesCategorias[4] && item.aquatico == "1") || (!arrayBotoesCategorias[4] && item.aquatico == "0") || (!arrayBotoesCategorias[4] && item.aquatico == "1")) { controlCategorias++; }else{ errorControlCategorias++; } break; case 5: if((arrayBotoesCategorias[5] && item.natureza == "1") || (!arrayBotoesCategorias[5] && item.natureza == "0") || (!arrayBotoesCategorias[5] && item.natureza == "1")) { controlCategorias++; }else{ errorControlCategorias++; } break; } } if(controlCategorias > 0 && errorControlCategorias == 0){ return itemSection; }