I want to create an array of all possible combinations of three variables that can either be true or false (i.e. 8 possible combinations).

I am trying to create the cube in the top left corner at this image

So the output should be something like

points = [ // first square { id: '000', truths: [false, false, false] position: [0, 0] }, { id: '100', truths: [true, false, false] position: [5, 0] }, { id: '010', truths: [false, true, false] position: [0, 5] }, { id: '110', truths: [true, true, false] position: [5, 5] }, // second square { id: '001', truths: [false, false, true] position: [2.5, 2.5] }, { id: '101', truths: [true, false, true] position: [7.5, 2.5] }, { id: '011', truths: [false, true, true] position: [2.5, 7.5] }, { id: '111', truths: [true, true, true] position: [7.5, 7.5] }, ]; lines = [ { from: '000', to: '100' }, { from: '000', to: '010' }, { from: '000', to: '001' }, { from: '100', to: '101' }, { from: '100', to: '110' }, { from: '001', to: '101' }, { from: '001', to: '011' }, { from: '101', to: '001' }, { from: '101', to: '111' }, ... ]

I don’t know how to go through all possible truth values and create these points.

One approach could be to use a for loop

for (var i=0; i<Math.pow(2, 3); i++) { ... }

but it doesn’t help me assigning the possible truth values.

## Answer

Everything in a computer is already binary. You don’t need any fancy `Math.pow`

or similar.

for (let i = 0; i < 1 << 3; i++) { console.log([!!(i & (1<<2)), !!(i & (1<<1)), !!(i & 1)]); }

While this looks nice and short, i am actually not a fan of `!!`

or magic numbers. I always fall for these tricks when writing snippets though. Therefore will attempt to give a slightly cleaner version:

const AMOUNT_OF_VARIABLES = 3; for (let i = 0; i < (1 << AMOUNT_OF_VARIABLES); i++) { let boolArr = []; //Increasing or decreasing depending on which direction //you want your array to represent the binary number for (let j = AMOUNT_OF_VARIABLES - 1; j >= 0; j--) { boolArr.push(Boolean(i & (1 << j))); } console.log(boolArr); }