I was practicing in Hackerrank JavaScript problems. I found one test which is called `Compare the triplets`

. This is the problem:

a = [1, 2, 3] b = [3, 2, 1] For elements *0*, Bob is awarded a point because a[0] . For the equal elements a[1] and b[1], no points are earned. Finally, for elements 2, a[2] > b[2] so Alice receives a point. The return array is [1, 1] with Alice's score first and Bob's second.

**I found the solution like this:**

let a = [17, 28, 30]; let b = [99, 16, 8]; function compareTriplets(a, b) { let scoreboard = [0, 0]; for (let i = 0; i < a.length; i++) { if (a[i] > b[i]) scoreboard[0]++ else if (a[i] < b[i]) scoreboard[1]++ } return scoreboard } compareTriplets(a, b)

I wanted to convert the ForLoop into `ForEach`

method. But I could not find the way to do that.

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## Answer

let a = [17, 28, 30]; let b = [99, 16, 8]; function compareTriplets(a, b) { let scoreboard = [0, 0]; a.forEach((element, i) => { if (element > b[i]) scoreboard[0]++ else if (element < b[i]) scoreboard[1]++ }); return scoreboard } compareTriplets(a, b)