I was practicing in Hackerrank JavaScript problems. I found one test which is called Compare the triplets. This is the problem: I found the solution like this: I wanted to convert the ForLoop into ForEach method. But I could not find the way to do that. Answer

Covert ForLoop to ForEach in Javascript

I was practicing in Hackerrank JavaScript problems. I found one test which is called Compare the triplets. This is the problem:

a = [1, 2, 3]
b = [3, 2, 1]
 For elements *0*, Bob is awarded a point because a[0] .
 For the equal elements a[1] and b[1], no points are earned.
 Finally, for elements 2, a[2] > b[2] so Alice receives a point.
 The return array is [1, 1] with Alice's score first and Bob's second.

I found the solution like this:

let a = [17, 28, 30];
let b = [99, 16, 8];
function compareTriplets(a, b) {
  let scoreboard = [0, 0];
  for (let i = 0; i < a.length; i++) {
    if (a[i] > b[i]) scoreboard[0]++
    else if (a[i] < b[i]) scoreboard[1]++
  }
  return scoreboard
}
compareTriplets(a, b)

I wanted to convert the ForLoop into ForEach method. But I could not find the way to do that.

Answer

let a = [17, 28, 30];
let b = [99, 16, 8];
function compareTriplets(a, b) {
  let scoreboard = [0, 0];
  a.forEach((element, i) => {
    if (element > b[i]) scoreboard[0]++
    else if (element < b[i]) scoreboard[1]++
  });
  return scoreboard
}
compareTriplets(a, b)

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Answer