I have a text line and I need capture the value “Keyword” key.
In this sample the value is “ConquestImageDate”.
With my code below I can capture the value as ConquestImageDate”.
But it has a ‘”‘ on the end.
I know I can use a replace to get rid off it.
But, I´d like to do it in the regex.
let line = '(0008,0023) VERS="CQ" VR="DA" VM="1" Keyword="ConquestImageDate" Name="Conquest Image Date"'; const re = /Keyword="s*(S+)/; m = re.exec(line); console.log(m[1]);
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Answer
You are not matching the closing "
, and as exec might yield null you can check for m
first before indexing into it.
let line = '(0008,0023) VERS="CQ" VR="DA" VM="1" Keyword="ConquestImageDate" Name="Conquest Image Date"'; const re = /Keyword="s*(S+)"/; m = re.exec(line); if (m) { console.log(m[1]); }
If there can also be unwanted whitespace chars at the end, you could making the S
non greedy.
let line = '(0008,0023) VERS="CQ" VR="DA" VM="1" Keyword="ConquestImageDate" Name="Conquest Image Date"'; const re = /Keyword="s*(S*?)s*"/; m = re.exec(line); if (m) { console.log(m[1]); }
You are matching Keyword
which is singular, but if in any case you want to match spaces or newlines as well between the double quotes
bKeyword="s*([^"]*?)"