I am using Sanity image url in my project and I am getting this error in my console page that says
This error pops up when ever I use the testimonial component in the react app> I am trying to make a portfolio but do not know how to fix this. I have ImageUrlBuilder worked fine in other components but it’s giving an error with this one.
const Testimonial = () => { const [currentIndex, setCurrentIndex] = useState(0); const [testimonials, setTestimonials] = useState([]); const [brands, setBrands] = useState([]); const handleClick = (index) => { setCurrentIndex(index); }; useEffect(() => { const query = '*[_type == "testimonials"]'; const brandsQuery = '*[_type == "brands"]'; client.fetch(query).then((data) => { setTestimonials(data); }); client.fetch(brandsQuery).then((data) => { setBrands(data); }); }, []); return ( <> {testimonials.length && ( <> <div className="app__testimonial-item app__flex"> <img src={urlFor(testimonials[currentIndex].imgurl)} alt={testimonials[currentIndex].name} /> <div className="app__testimonial-content"> <p className="p-text">{testimonials[currentIndex].feedback}</p> <div> <h4 className="bold-text">{testimonials[currentIndex].name}</h4> <h5 className="p-text">{testimonials[currentIndex].company}</h5> </div> </div> </div> <div className="app__testimonial-btns app__flex"> <div className="app__flex" onClick={() => handleClick(currentIndex === 0 ? testimonials.length - 1 : currentIndex - 1)}> <HiChevronLeft /> </div> <div className="app__flex" onClick={() => handleClick(currentIndex === testimonials.length - 1 ? 0 : currentIndex + 1)}> <HiChevronRight /> </div> </div> </> )} <div className="app__testimonial-brands app__flex"> {brands.map((brand) => ( <motion.div whileInView={{ opacity: [0, 1] }} transition={{ duration: 0.5, type: 'tween' }} key={brand._id} > <img src={urlFor(brand.imgUrl)} alt={brand.name} /> </motion.div> ))} </div> </> ); }; export default AppWrap( MotionWrap(Testimonial, 'app__testimonial'), 'testimonial', 'app__primarybg', );
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Answer
Did you read the docs?
urlFor(testimonials[currentIndex].imgurl).url()