I tried this: And my Node class: here head is the main LinkedList’s head, and HEAD is the head of new one. I’m using stack here. And the algorithm is in linear complexity. Instead of creating new Node everytime, I think there is some better way to implement this. Can you suggest some other ways? Also is it possible to
Tag: linked-list
LeetCode Remove Nth Node From End of List – Linked List [closed]
Closed. This question needs debugging details. It is not currently accepting answers. Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question. Closed 9 months ago. Improve this question I came across this answer on LeetCode for the “Remove Nth Node From
javascript – simple linked list traversal issue
I have implemented a single linked list using javascript. Please find the code below: But the traverse method never prints the last element. What am I missing here? The insertAtTail method looks correct though. Could anyone please let me know. thanks Answer In the traverse, you need to check all nodes not until the next one is null. so I
I have a quick question about how this linked list merging code works
Im confused on how head.next returns the entire list instead of a next value such l1,l2,dummy .next does in the code below. particularly I’m wondering how head.next returns an entire sorted array and skips the -1 value that was input on the second line. Answer Maybe it helps when visualising how the list is built: Let the input be a