I have to get the result from this regular expression; the regular expression is a string in a variable:
const dataFileUrlRegExpr = new RegExp( "\/home-affairs\/document\/download\/([\\w-]{1,})_en?filename=visa_statistics_for_consulates_20[0-9]{2}.xlsx" ); href = '/home-affairs/document/download/75ecba81-12db-42b0-a628-795d3292c680_en?filename=visa_statistics_for_consulates_2020.xlsx' xlslHrefRegExpResult = dataFileUrlRegExpr.exec(xlslHref);
but the xlslHrefRegExpResult variable is null.
If I use:
const dataFileUrlRegExpr = new RegExp( //home-affairs/document/download/([w-]{1,})_en?filename=visa_statistics_for_consulates_20[0-9]{2}.xlsx/g );
without the string variable containing the expression, the result is achieved.
Where is the error using a string to build the regexp?
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Answer
The correct code should be:
const dataFileUrlRegExpr = new RegExp( "\/home-affairs\/document\/download\/([\w-]{1,})_en\?filename=visa_statistics_for_consulates_20[0-9]{2}.xlsx", 'g' ); href = '/home-affairs/document/download/75ecba81-12db-42b0-a628-795d3292c680_en?filename=visa_statistics_for_consulates_2020.xlsx' xlslHrefRegExpResult = dataFileUrlRegExpr.exec(href); console.log(xlslHrefRegExpResult)
You had too many backslashes in [\\w-]
, and you were missing the backslashes before ?
./