In ES6, is it possible to shorten the following code. I have an App.js
file and an index.js
.
index.js
import App from './App'; export default App;
Something like this
index.js
export default App from './App.js'
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Answer
If you use proposal-export-default-from
Babel plugin (which is a part of stage-1
preset), you’ll be able to re-export default using the following code:
export default from "./App.js"
For more information see the ECMAScript proposal.
Another way (without this plugin) is:
export { default as App } from "./App.js"
The above is a very common practice when separate files, each with its own export
, have all something in common, for example, utils
, so if, for example, one would want to import 3 utility functions, instead of having to write multiple imports:
import util_a from 'utils/util_a' import util_b from 'utils/util_b' import util_c from 'utils/util_c'
One could import any of the utilities in a single-line:
import { util_a, util_b , util_c } from 'utils'
By creating an index.js
file in the /utils
folder and import all the defaults of all the utilities there and re-export, so the index
file will serve as the “gateway” for all imports related to that folder.