I want to print numbers in pattern as below also I need this to print using only one for loop not in if condition inside for loop.
If I give s = 7
the output pattern would be 7, 5, 3, 1, 3, 5, 7
If s=6
then output is 6, 4, 2, 4, 6
This is what I tried but not successful.
const s = 7, b = 2 for (x = s, d = b; x > 0 && x <= 7; x -= 2) { console.log(x) }
I don’t want to use any pre-built libraries to achieve this such as Math.abs()
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Answer
With ternary operator:
const s = 10, b = 2 for (x = s, step = -b; x <= s; step = x + step <= 0 ? -step : step, x += step) { console.log(x) }