I need some help with my code as I have got a problem with posting the value. When I click on the radio, it will not post the data when it redirect me to secondpage.php. I want to post the value when I click on the radio button to take me to the next page.
firstpage.php
<table> <form name="frmProfile" method="post" action="secondpage.php"> <tr> <td>gender</td> <td><input type="radio" name="gender" onclick="document.location.href='http://example.com/secondpage.php'" data-gender="female" value="female">Female <input type="radio" name="gender" onclick="document.location.href='http://example.com/secondpage.php'" data-gender="male" value="male">Male</td> </tr> <tr><td colspan="2"><input type="submit" name="submit" value="Submit" /></td></tr> </form> </table>
secondpage.php
print_r($_POST); ?>
It will show the empty data in the $_POST
as I will get the results which it show Array ( )
when I am using print_r($_POST)
in secondpage.php.
What I am trying to achieve is when I click on a radio button, I want to post the data to redirect me to secondpage.php
and display the data of Male
or Female
depends on the radio button that I click on.
Can you please show me an example how I could post the value of the radio that I select on to redirect me to the secondpage.php to display the data of $_POST
?
Thank you.
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Answer
You can bind a click event listener to the form. When a click happens, check if it originated from one of the radio elements. If it did, submit the form.
document.getElementById('genderForm').addEventListener('click', function(e){ // 'this' is the genderForm if (e.target.name === 'gender') this.submit(); });
<form id="genderForm" name="frmProfile" method="post" action="secondpage.php"> <table> <tr> <td>gender</td> <td> <input type="radio" name="gender" value="female">Female <input type="radio" name="gender" value="male">Male </td> </tr> </table> </form>