I have a father div with X number of child divs. What I’m trying to do is to loop throught all the child elements and alternate some styles. For example (having 4 child divs)
- Child 1 style = nothing;
- Child 2 style = font-size: 24px;
- Child 3 style = nothing;
- Child 4 style = font-size: 24px;
At the moment this is what I have:
$('#fatherDiv > div').each(function() { if ($(this).css("background-color") !== 'red') { $(this).css("background-color", "red"); } });
With this code I’m able to loop throught all the childs but it seems that the if condition is wrong. I guess that I need to the the comparision but with the previous child instead of the current, so how can I do that? And is this #div > div.each the best way to loop throught the elements?
Here is a fiddle to play with.
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Answer
You can do this with simple CSS
without javascript
. Use selector nth-of-type(odd)
& nth-of-type(even)
(alternatively you can use nth-child(odd)
& nth-child(even)
) and assign your desired style.
References
- https://www.w3schools.com/cssref/css_selectors.asp
- https://www.w3.org/Style/Examples/007/evenodd.en.html
Try it below.
#fatherDiv > div:nth-of-type(even) { background-color: red; } #fatherDiv > div:nth-of-type(odd) { background-color: green; }
<div id="fatherDiv"> <div id="childDiv1"> <h4>Div 1</h4> </div> <div id="childDiv2"> <h4>Div 2</h4> </div> <div id="childDiv3"> <h4>Div 3</h4> </div> <div id="childDiv4"> <h4>Div 4</h4> </div> <div id="childDiv5"> <h4>Div 5</h4> </div> <div id="childDiv6"> <h4>Div 6</h4> </div> <div id="childDiv7"> <h4>Div 7</h4> </div> </div>