Javascript sort function. Sort by First then by Second

I have an array of objects to sort. Each object has two parameters: Strength and Name

objects = []
object[0] = {strength: 3, name: "Leo"}
object[1] = {strength: 3, name: "Mike"}

I want to sort first by Strength and then by name alphabetically. I am using the following code to sort by the first parameter. How do I sort then by the second?

function sortF(ob1,ob2) {
  if (ob1.strength > ob2.strength) {return 1}
  else if (ob1.strength < ob2.strength){return -1}
  return 0;
};

Thanks for your help.

(I am using Array.sort() with the aforementioned sortF as the sort comparison function passed into it.)

Answer

Expand your sort function to be like this;

function sortF(ob1,ob2) {
    if (ob1.strength > ob2.strength) {
        return 1;
    } else if (ob1.strength < ob2.strength) { 
        return -1;
    }

    // Else go to the 2nd item
    if (ob1.name < ob2.name) { 
        return -1;
    } else if (ob1.name > ob2.name) {
        return 1
    } else { // nothing to split them
        return 0;
    }
}

A < and > comparison on strings is an alphabetic comparison.