function myFunction2() { for (let i=1; i < 3; i++){ if (i<2){ var numhex = (Math.random() * 0xfffff * 1000000).toString(16); var hex1 = '#' + numhex.slice(0, 6); // return hex1; // console.log(hex1); } else { var numhex = (Math.random() * 0xfffff * 1000000).toString(16); var hex2 = '#' + numhex.slice(0, 6); // return hex2; // console.log(hex2); } } // document.getElementById("container").style.backgroundImage = "linear-gradient(to right, " + {hex1} + ", " + {hex2} + ")"; document.getElementById("container").setProperty("background-image", "linear-gradient(to right, " + {hex1} + ", " + {hex2}); document.getElementById("description").innerHTML = "The code of the color is: linear-gradient( 270deg, " + hex1 + ", " + hex2 + " );"; };
Hello, I am trying to set two colors for linear-gradient as parameters inside a specific element’s background-image property, but it seems that something is wrong with my setProperty. Everything is working fine except this line of code. I’ve also tried it with style.backgroundImage with no result. I am new to js. Thanks in advance
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Answer
Use below code . It worked
document.getElementById('container').style.background = `linear-gradient(to right, ${hex1} , ${hex2} )`;