How to find longer Strings from an Array?

I want to find Longer Strings from this array:

const myArr = [“first”, “second”, “third”, “fourth”, “fifth”, “sixth”, “seven”, “eighth”]

in this array “second”,”fourth”,”eighth” has length of 6. I want to return these in an array.

const myArr = ["first", "second", "third", "fourth", "fifth", "sixth", "seven", "eighth"]

function longerStrings(arr) {
    let largeStrings = []
    let longerWord = ''
    for (let name of arr) {
        if (name.length > longerWord.length) {
            longerWord = name
            largeStrings.push(longerWord)
        }
    }
    return largeStrings
}
longerStrings(myArr)

expected output is: [“second”,”fourth”,”eighth”]

but returns =[“first”,”second”]

Answer

Easier if you use filter instead:

const myArr = ["first", "second", "third", "fourth", "fifth", "sixth", "seven", "eighth"]
const longest = myArr.reduce((a, b) =>  a.length > b.length ? a : b);
const res = myArr.filter(el => el.length >= longest.length)
console.log(res)

That returns:

["second","fourth","eighth"]

Or, as Sash mentions below, it can be done in a single pass, although the solution is not as readable:

let max = 0;
const reducer = myArray.reduce((previous, current) => {
  if (current.length > max) {
    previous = [];
  }
  if (current.length >= max) {
    previous.push(current);
    max = current.length;
  }
  return previous;
}, []);

console.log(reducer);