let array1= [ { "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]}, { "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]}, { "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]} ]; const array2= ['2012'];
Result I wanted
{ "id": 100, name: "A", "details": [{"year": "2012"}]}
I know i can filter the array with this code
array1.filter(o => o.details.some(p=> { return array2.includes(p.year) }) )
But is there a way to remove the objects as well.
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Answer
We can reduce to avoid multiple steps
This reduce filters and deletes part of the details array
let array1 = [ { "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]}, { "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]}, { "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]} ]; const array2 = ['2012']; let array3 = array1.reduce((acc, {id,name,details}) => { if (array2.includes(details[0].year)) { acc.push({ id, name, details: details[0] }) } return acc }, []) console.log(array3)