JavaScript
x
10
10
1
var arr = [2, 6, 4, 4, 4, 9]
2
var newArr = (arr.sort())
3
4
for (var i = 0; i < newArr.length; i++)
5
if (newArr[i] == newArr[i + 1]) {
6
var rem = [console.log(i)] //- (a)
7
8
}
9
console.log(rem[0])
10
I want all the values of i
for which the number is repeating in newArr
array. Statement (a) gives me the indices and I want to store them in an array named rem
. However console.log(rem[0])
is undefined. What can I do?
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Answer
you mean this?
JavaScript
1
10
10
1
var arr = [2, 6, 4, 4, 4, 9]
2
var newArr = (arr.sort())
3
var rem = []; // create your rem array outside
4
for (var i = 0; i < newArr.length; i++) {
5
if (newArr[i] == newArr[i + 1]) {
6
rem.push(i); // if "i" matches your criteria, add it to the array.
7
}
8
}
9
console.log(rem); // rem has the full list of indices
10