I’m trying to create live search filter,with ajax
$(function() {
$('#search-item').keyup(function() {
$.ajax({
type: "GET",
url: "/toysprices/",
data: {
'query' : $('#search-toy').val(),
'csrfmiddlewaretoken' : $("input[name=csrfmiddlewaretoken]").val()
},
success: searchSuccess,
dataType: 'html'
});
});
});
function searchSuccess(data, textStatus, jqXHR)
{
console.log(data);
}
and my views.py
f request.method == "GET":
search_text = request.GET['query']
if search_text:
search_text = request.GET['query']
statuss = Status.objects.filter(status__contains = search_text)
else:
statuss = Status.objects.all()
return render(request, 'ajax_search.html', {'statuss':statuss})
it works correctly, but it returns whole html page, how can i make to get only part which I want to render in my template.
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Answer
Returning the result with JSON will solve your problem.
For Example,
# Django view
def search(request):
if request.method == "GET":
return_array = []
search_text = request.GET.get('query') # Always put request.GET.get('param') instead of request.GET['param']
if search_text:
search_text = request.GET.get('query')
statuss = Status.objects.filter(status__icontains = search_text)
else:
statuss = Status.objects.all()
for i in statuss:
return_sub_array = {}
return_sub_array['status_name'] = i.status_name
return_array.append(return_sub_array)
return HttpResponse(json.dumps(return_array))
# Jquery function
$('#search-item').keyup(function() {
$.ajax({
type: "GET",
url: "/toysprices/",
dataType: 'JSON',
data: {
'query' : $('#search-toy').val(),
'csrfmiddlewaretoken' : $("input[name=csrfmiddlewaretoken]").val()
},
success: function(data){
if(data.length > 0 )
{
console.log(data);
for (var i = 0; i < data.length ; i++) {
var obj = data[i]['status_name'];
console.log(obj)
// further logic goes here
}
}
else {
console.log("No result found");
}
},
error:function(data){
console.log('error')
console.log(data)
}
});
});