# compare 2d array against another 2d array by checking arrays with same elements

Have a 2d array (Arr1) and not able to get a check/compare against another 2d array (Arr2) to count arrays what match with exact elements. for example:

```const arr1: string[][] = [
["R", "P"],
["R", "S"],
["S", "P"],
];
const checkAgainst: string[][] = [
["R", "S"],
["P", "R"],
["S", "P"],
];

function check(arr1: string[][]) {
arr1.map((a, index, arr) => {
let result = arr[0].filter((o1) =>
checkAgainst.some((o2) => o1.id === o2.id)
);
});
}
console.log(check(arr1));
```

Return should be `true, false, true` or just `1, 0, 1`, so in the end can count amount of `true or 1`, expected outcome: `true===2`

Any good way to do that without using for loops?

```function haveSameValues(arr1: string[], arr2: string[]): boolean {
if (arr1.length === 0 || arr1.length != arr2.length) {
return false;
}

for (let i = 0; i < arr1.length; i++) {
if (arr1[i] != arr2[i]) {
return false;
}
}

return true;
}

function countMatches(matrix1: string[][], matrix2: string[][]): number {
let count = 0;

for (const arr1 of matrix1) {
for (const arr2 of matrix2) {
if (haveSameValues(arr1, arr2) {
count++;
}
}
}

return count;
}

const arr1: string[][] = [
["R", "P"],
["R", "S"],
["S", "P"],
];
const checkAgainst: string[][] = [
["R", "S"],
["P", "R"],
["S", "P"],
];

console.log(countMatches(arr1, checkAgainst));
```