Can I get a JSON object with name value?

I’m trying to make a Covid-19 tracker App by ReactJS. I want to get data that only an object (a specific province value) from JSON API with ProvinceChange event.

Problem :

I can’t get data that is only an object (a specific province value).

what I tried :

I tried a method filter using province.name but is not work, as I get

Sample JSON API :

[
{
    "txn_date": "2022-03-07",
    "province": "กระบี่",
    "new_case": 112,
    "total_case": 18101,
    "new_case_excludeabroad": 112,
    "total_case_excludeabroad": 17838,
    "new_death": 2,
    "total_death": 93,
    "update_date": "2022-03-07 07:20:43"
},
{
    "txn_date": "2022-03-07",
    "province": "กรุงเทพมหานคร",
    "new_case": 2815,
    "total_case": 590810,
    "new_case_excludeabroad": 2809,
    "total_case_excludeabroad": 587121,
    "new_death": 7,
    "total_death": 7126,
    "update_date": "2022-03-07 07:20:43"
},
{
    "txn_date": "2022-03-07",
    "province": "กาญจนบุรี",
    "new_case": 176,
    "total_case": 33734,
    "new_case_excludeabroad": 176,
    "total_case_excludeabroad": 33684,
    "new_death": 2,
    "total_death": 214,
    "update_date": "2022-03-07 07:20:43"
},
{
    "txn_date": "2022-03-07",
    "province": "กาฬสินธุ์",
    "new_case": 214,
    "total_case": 18163,
    "new_case_excludeabroad": 214,
    "total_case_excludeabroad": 18159,
    "new_death": 0,
    "total_death": 97,
    "update_date": "2022-03-07 07:20:43"
},]

This is my code :

const App = ()=>{
  const [provinces, setProvinces] = useState([]);
  const [province, setProvince] = useState("thailand");
  const [provinceInfo, setProvinceInfo] = useState({});

  useEffect(() => {
   
   const getProvincesData = async  () => {
     fetch("https://covid19.ddc.moph.go.th/api/Cases/today-cases-by-provinces")
      .then((response) => response.json())
      .then((data) => {
        const provinces = data.map((province) => ({
          name: province.province,
        }));
        setProvinces(provinces);
      });
   };
  
    getProvincesData();
  }, []); 

  const onProvinceChange = async (event) =>{
    const provinceCode = event.target.value;
    //setProvince(provinceCode);

    const url = 
      provinceCode === "thailand"
       ? "https://covid19.ddc.moph.go.th/api/Cases/today-cases-all"
       : 'https://covid19.ddc.moph.go.th/api/Cases/today-cases-by-provinces' ;

    await fetch(url)
    .then(response => response.json())
    .then(data => {
      const provinceInfo = data.filter((data) => {
          return data.name === '{province.name}'
        })
        setProvince(provinceCode);
      // All of the data from the province response
        setProvinceInfo(data);
        });
    
    };
  
  console.log(provinceInfo);

  return (
    <div className="app">
      <div className='app__left'>
        <div className="app__header">
          <h1>COVID-19 TRACKER in Thailand</h1>
          <FormControl>
            <Select variant="outlined" onChange={onProvinceChange} value={province}>
              <MenuItem value="thailand">ประเทศไทย</MenuItem>
              {provinces.map((province) => (
                <MenuItem value={province.name}>{province.name}</MenuItem>     // Loop through all the province and show drop down list of the option 
              ))}

            </Select>
          </FormControl>
       </div>
    </div>
  
  );
}

Answer

If I’m understanding correctly, it looks like you’re trying to set provinceInfo to the single province you’re searching for by provinceCode. There are two changes to make if that’s the case:

'{province.name}'is a string. I think you need to change that to provinceCode which is a variable reference set to the province you want.
It looks like you’re trying to set provinceInfo to an object. .filer() will return an array with only items matching, so you probably want .find() instead, which returns just one.

So you can change:

const provinceInfo = data.filter((data) => {
  return data.name === '{province.name}'
})

To…

const provinceInfo = data.find((province) =>  province.name === provinceCode)

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Answer