DEFINITION
I have connected my cube js backend to mongodb. I am storing documents inside my mongo db database in a following way.
THIS IS HOW MY DOCUMENT LOOKS LIKE IN MONGO DB
{ anonymousId: "bdee014b-09e1-4d79-bcf1-c3cc91cd4101" user: "abc" url: "/index" eventType: "pageView" date: "22-08-2020" time: "20:33:9" data: "some data" }
So now let us assume that I have 10 documents in my mongodb collection in which 5 documents belong to user: “abc” and 5 documents belong to user: “xyz”.
HOW I GET THE DATA RIGHT NOW IN THE BROWSER CONSOLE IS SHOWN BELOW
{ annotation: {measures: {,…},…} data: [{Events.user: "xyz",…}, {Events.user: "xyz",…}, {Events.user: "xyz",…},…] 0: {Events.user: "xyz",…} 1: {Events.user: "xyz",…} 2: {Events.user: "xyz",…} 3: {Events.user: "abc",…} 4: {Events.user: "abc",…} 5: {Events.user: "xyz",…} lastRefreshTime: "2020-08-22T15:23:53.547Z" query: {measures: ["Events.pageView", "Events.buttonClick"], dimensions: ["Events.user", "Events.allData"],…} refreshKeyValues: [[{unix_timestamp(): 1598109833}]] usedPreAggregations: {} }
Here you can see in the data array that i get back as a response from the cube js backend has 6 objects in 4 of them belong to user XYZ and 2 of them belong to ABC.
MY CUBE.JS SCHEMA
cube(`Events`, { sql: `SELECT * FROM test.events`, refreshKey: { sql: `SELECT UNIX_TIMESTAMP()` }, measures: { count: { type: `count` }, pageView: { type: `count`, filters: [ { sql: `${eventType} = 'pageView'` } ] }, buttonClick: { type: `count`, filters: [ { sql: `${eventType} = 'buttonClicked'` } ] } }, dimensions: { anonymousId: { sql: `anonymousId`, type: `string` }, url: { sql: `url`, type: `string` }, user: { sql: `user`, type: `string` }, allData: { sql: `data`, type: `string` }, eventType: { sql: `eventType`, type: `string` }, referrer: { sql: `referrer`, type: `string` }, } });
QUESTION
How can i segregate or we can say group data depending upon the user. What i mean is that i want the data to return two arrays for two different users. Lets say if xyz has 2 documents an array of 2 documents for that very user should be returned and abc has 4 documents an array of 4 documents should be returned.
They should not be returned combined. abc’s data should be returned seperately and xyz’s data should be returned seperately.
2 USERS SHOULD MAINTAIN 2 DIFFERENT ARRAYS
EXPECTATION
A trick or a way by which we write the schema in achieving this behavior,
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Answer
You can use User Context or queryTransformer or Multitenant Compile Context, these three functions allow you to implement data access based on authorization data.
queryTransformer is a little more complicated, but it will allow you to customize access control more flexibly. It is better suited for complex cases.